define type_transform to new user defined type
| От | Mohsen SM |
|---|---|
| Тема | define type_transform to new user defined type |
| Дата | |
| Msg-id | CAGT6x6d_=QxqGdovy3u1ncBvz5__z-1m_GSQAVRPOWeAA3_awQ@mail.gmail.com обсуждение исходный текст |
| Ответы |
Re: define type_transform to new user defined type
|
| Список | pgsql-hackers |
<div dir="ltr"><div style="font-family:arial,sans-serif;font-size:12.727272033691406px"> I want to create new type that issimilar to varchar.</div><div style="font-family:arial,sans-serif;font-size:12.727272033691406px">its size is variable.</div><divstyle="font-family:arial,sans-serif;font-size:12.727272033691406px">I use CREATE TYPE query.</div><divstyle="font-family:arial,sans-serif;font-size:12.727272033691406px">I define for that type this functions:</div><divstyle="font-family:arial,sans-serif;font-size:12.727272033691406px"> 1-typein</div><div style="font-family:arial,sans-serif;font-size:12.727272033691406px">2-typeoute</div><div style="font-family:arial,sans-serif;font-size:12.727272033691406px">3-typemodify_input</div><div style="font-family:arial,sans-serif;font-size:12.727272033691406px">4-typemodify_output</div><div style="font-family:arial,sans-serif;font-size:12.727272033691406px">5-type_transform</div><div style="font-family:arial,sans-serif;font-size:12.727272033691406px">Ican define 1 to 4 functions in CREATE TYPE</div><divstyle="font-family:arial,sans-serif;font-size:12.727272033691406px">but I can't define type_transform for thattype. how did I can define type_transform for that type?</div></div>
В списке pgsql-hackers по дате отправления: