Re: Why this regexp matches?!
| От | Szymon Guz |
|---|---|
| Тема | Re: Why this regexp matches?! |
| Дата | |
| Msg-id | CAFjNrYvOVm98tp=RcxnR95MCKKLQ=9ajXVw3F84exK=+ZLjZoA@mail.gmail.com обсуждение исходный текст |
| Ответ на | Why this regexp matches?! (hubert depesz lubaczewski <depesz@depesz.com>) |
| Ответы |
Re: Why this regexp matches?!
|
| Список | pgsql-general |
On 4 February 2012 09:46, hubert depesz lubaczewski <depesz@depesz.com> wrote:
select 'depesz depeszx depesz' ~ E'^(.*)( \\1)+$';
what's worse:
$ select regexp_replace( 'depesz depeszx depesz', E'^(.*)( \\1)+$', E'\\1' );
regexp_replace
────────────────
depesz
(1 row)
I know that Pg regexps are limited, but even grep's regexps match this
correctly:
=$ printf 'depesz depesz depesz\ndepesz depeszx depesz\n' | grep -E '^(.*)( \1)+$';
depesz depesz depesz
Best regards,
depesz
Hi,
some time ago I hit the same problem, however the solution was a little bit tricky. I didn't have time to investigate it, but this works:
postgres@postgres:5840=# select regexp_replace( 'depesz depeszx depesz', E'^(.*)( \\\\1)+$', E'\\\\1' );
regexp_replace
-----------------------
depesz depeszx depesz
(1 row)
regards
Szymon
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