Problem while updating a foreign table pointing to a partitionedtable on foreign server
От | Ashutosh Bapat |
---|---|
Тема | Problem while updating a foreign table pointing to a partitionedtable on foreign server |
Дата | |
Msg-id | CAFjFpRfcgwsHRmpvoOK-GUQi-n8MgAS+OxcQo=aBDn1COywmcg@mail.gmail.com обсуждение исходный текст |
Ответы |
Re: Problem while updating a foreign table pointing to apartitioned table on foreign server
Re: Problem while updating a foreign table pointing to a partitionedtable on foreign server |
Список | pgsql-hackers |
Hi, Consider this scenario postgres=# CREATE TABLE plt (a int, b int) PARTITION BY LIST(a); postgres=# CREATE TABLE plt_p1 PARTITION OF plt FOR VALUES IN (1); postgres=# CREATE TABLE plt_p2 PARTITION OF plt FOR VALUES IN (2); postgres=# INSERT INTO plt VALUES (1, 1), (2, 2); postgres=# CREATE FOREIGN TABLE fplt (a int, b int) SERVER loopback OPTIONS (table_name 'plt'); postgres=# SELECT tableoid::regclass, ctid, * FROM fplt; tableoid | ctid | a | b ----------+-------+---+--- fplt | (0,1) | 1 | 1 fplt | (0,1) | 2 | 2 (2 rows) -- Need to use random() so that following update doesn't turn into a direct UPDATE. postgres=# EXPLAIN (VERBOSE, COSTS OFF) postgres-# UPDATE fplt SET b = (CASE WHEN random() <= 1 THEN 10 ELSE 20 END) WHERE a = 1; QUERY PLAN -------------------------------------------------------------------------------------------- Update on public.fplt Remote SQL: UPDATE public.plt SET b = $2 WHERE ctid = $1 -> Foreign Scan on public.fplt Output: a, CASE WHEN (random() <= '1'::double precision) THEN 10 ELSE 20 END, ctid Remote SQL: SELECT a, ctid FROM public.plt WHERE ((a = 1)) FOR UPDATE (5 rows) postgres=# UPDATE fplt SET b = (CASE WHEN random() <= 1 THEN 10 ELSE 20 END) WHERE a = 1; postgres=# SELECT tableoid::regclass, ctid, * FROM fplt; tableoid | ctid | a | b ----------+-------+---+---- fplt | (0,2) | 1 | 10 fplt | (0,2) | 2 | 10 (2 rows) We expect only 1 row with a = 1 to be updated, but both the rows get updated. This happens because both the rows has ctid = (0, 1) and that's the only qualification used for UPDATE and DELETE. Thus when a non-direct UPDATE is run on a foreign table which points to a partitioned table or inheritance hierarchy on the foreign server, it will update rows from all child table which have ctids same as the qualifying rows. Same is the case with DELETE. There are two ways to fix this 1. Use WHERE CURRENT OF with cursors to update rows. This means that we fetch only one row at a time and update it. This can slow down the execution drastically. 2. Along with ctid use tableoid as a qualifier i.e. WHERE clause of UPDATE/DELETE statement has ctid = $1 AND tableoid = $2 as conditions. PFA patch along the lines of 2nd approach and along with the testcases. The idea is to inject tableoid attribute to be fetched from the foreign server similar to ctid and then add it to the DML statement being constructed. It does fix the problem. But the patch as is interferes with the way we handle tableoid currently. That can be seen from the regression diffs that the patch causes. RIght now, every tableoid reference gets converted into the tableoid of the foreign table (and not the tableoid of the foreign table). Somehow we need to differentiate between the tableoid injected for DML and tableoid references added by the user in the original query and then use tableoid on the foreign server for the first and local foreign table's oid for the second. Right now, I don't see a simple way to do that. -- Best Wishes, Ashutosh Bapat EnterpriseDB Corporation The Postgres Database Company
Вложения
В списке pgsql-hackers по дате отправления: