Re: The mysterious pg_proc.protrftypes
От | Pavel Stehule |
---|---|
Тема | Re: The mysterious pg_proc.protrftypes |
Дата | |
Msg-id | CAFj8pRAB9BmrfOc0esavUEi--0xQdFO8GTSsfAfSWwHWnF5bhA@mail.gmail.com обсуждение исходный текст |
Ответ на | The mysterious pg_proc.protrftypes ("Joel Jacobson" <joel@compiler.org>) |
Ответы |
Re: The mysterious pg_proc.protrftypes
|
Список | pgsql-hackers |
po 25. 1. 2021 v 8:05 odesílatel Joel Jacobson <joel@compiler.org> napsal:
Hi,I'm trying to understand how pg_proc.protrftypes works.The documentation says "Data type OIDs for which to apply transforms.".For this column, there is no reference to any catalog table?I would guess it should be "(references pg_type.oid)", right?I tried to generate a value for this column to verify my hypothesis,but I struggle to find an example that produces a not null value here.I grepped the sources and found the "CREATE TRANSFORM FOR type_name" command,and found an extension using it named "bool_plperl" which I installed.I assumed this would cause a value, but no.Both of bool_plperl's two functions get null pg_proc.protrftypes values.I've tried running the full regression "make installcheck", but protrftypes doesn't seem to be covered:$ cd postgresql$ make installcheck...=======================All 203 tests passed.=======================$ psql regressionregression=# SELECT COUNT(*) FROM pg_proc WHERE protrftypes IS NOT NULL;count-------0(1 row)Can someone please show me how to generate a function with a not null pg_proc.protrftypes value?
you should to use TRANSFORM clause in CREATE FUNCTION statement
CREATE EXTENSION hstore_plperl CASCADE;
CREATE FUNCTION test2() RETURNS hstore
LANGUAGE plperl
TRANSFORM FOR TYPE hstore
AS $$
$val = {a => 1, b => 'boo', c => undef};
return $val;
$$;
LANGUAGE plperl
TRANSFORM FOR TYPE hstore
AS $$
$val = {a => 1, b => 'boo', c => undef};
return $val;
$$;
Regards
Pavel
Many thanks./Joel
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