Re: pgbench - allow to create partitioned tables

On Wed, Sep 18, 2019 at 1:02 PM Fabien COELHO <coelho@cri.ensmp.fr> wrote:
>
*/
+ res = PQexec(con,
+ "select o.n, p.partstrat, pg_catalog.count(p.partrelid) "
+ "from pg_catalog.pg_class as c "
+ "join pg_catalog.pg_namespace as n on (n.oid = c.relnamespace) "
+ "cross join lateral (select
pg_catalog.array_position(pg_catalog.current_schemas(true),
n.nspname)) as o(n) "
+ "left join pg_catalog.pg_partitioned_table as p on (p.partrelid = c.oid) "
+ "left join pg_catalog.pg_inherits as i on (c.oid = i.inhparent) "
+ /* right name and schema in search_path */
+ "where c.relname = 'pgbench_accounts' and o.n is not null "
+ "group by 1, 2 "
+ "order by 1 asc "

I have a question, wouldn't it be sufficient to just group by 1?  Are
you expecting multiple pgbench_account tables partitioned by different
strategy under the same schema?

-- 
Regards,
Dilip Kumar
EnterpriseDB: http://www.enterprisedb.com