Re: Should "select 'nan'::float = 'nan'::float;" return false as per IEEE 754
От | Thomas Munro |
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Тема | Re: Should "select 'nan'::float = 'nan'::float;" return false as per IEEE 754 |
Дата | |
Msg-id | CADLWmXVhkYeH068-JTVn2E-VcLUprsTOGuK=rZHN_o5FuH9bKA@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Should "select 'nan'::float = 'nan'::float;" return false as per IEEE 754 (Hannu Krosing <hannu@2ndQuadrant.com>) |
Список | pgsql-hackers |
On 28 October 2012 10:37, Hannu Krosing <hannu@2ndquadrant.com> wrote: > On 10/28/2012 11:21 AM, Thomas Munro wrote: >> >> On 28 October 2012 09:43, Hannu Krosing <hannu@2ndquadrant.com> wrote: >>> >>> This is how PostgreSQL currently works - >>> >>> test=# select 'NaN'::float = 'NaN'::float as must_be_false; >>> must_be_false >>> ---------- >>> t >>> (1 row) >>> >>> I think that PostgreSQL's behaviour of comparing two >>> NaN-s as equal is wrong and Iwe should follow the IEEE 754 spec here >>> >>> As per IEEE 754 a NaN behaves similar to NULL in SQL. >> >> FWIW there is a note in the documentation about this: >> >> "Note: IEEE754 specifies that NaN should not compare equal to any >> other floating-point value (including NaN). In order to allow >> floating-point values to be sorted and used in tree-based indexes, >> PostgreSQL treats NaN values as equal, and greater than all non-NaN >> values." > > I wonder how hard it would be to start treating NaNs as NULLs > so you could say ORDER BY fvalue NULLS AND NANS LAST :) If you want to treat NaN like NULL, there are some other situations to think about: hack=> create table foo (x float); CREATE TABLE hack=> insert into foo values ('NaN'::float), (42); INSERT 0 2 hack=> select sum(x) from foo;sum -----NaN (1 row) That is the same result as evaluating 'NaN'::float + 42. hack=> delete from foo; DELETE 2 hack=> insert into foo values (null), (42); INSERT 0 2 hack=> select sum(x) from foo;sum ----- 42 (1 row) That is not the same results as evaluating NULL + 42 (the SUM aggregate skips NULLs). The trouble is, NULL is not a value within the type T (float in this case), it's more like a nullable value has type NULL | T. The algebra(set of operators including SUM, +, < etc) for thealgebraic type NULL | T doesn't behave the same way as the algebra for T, whereas NaN is one of the values that IEEE float can hold, so it's part of the T in this case. In other words, for NaNs, if you have one set of operators used by aggregates, ORDER BY, btrees and another set of operators <, >, = for use in user expressions, that would be (at least subtly) different than what happens today with NULL. Well, I'm not that sure of what I'm saying. But I have thought about it for a while, as I have been (very slowly) working on an extension which provides IEEE 754-2008 decimal number types DECIMAL32, DECIMAL64, DECIMAL 128 (they have the same NaN, -0, +0, -Inf, +Inf shenanigans, and some more fun problems as well, like non-normal numbers, so that you can represent 1.002 and 1.0020 as distinct bit patterns, and then have to argue with yourself about what it all means).
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