Re: regexp_replace behavior
От | Marcin Krawczyk |
---|---|
Тема | Re: regexp_replace behavior |
Дата | |
Msg-id | CABnqL329i_eb7fUa3iGpG=_SHpLrkd_wG4hfF1SQosyAqQgzUg@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: regexp_replace behavior (Alvaro Herrera <alvherre@2ndquadrant.com>) |
Список | pgsql-sql |
Yes that's exactly what I needed. Thanks a lot.
pozdrowienia
mk
pozdrowienia
mk
2012/11/20 Alvaro Herrera <alvherre@2ndquadrant.com>
Marcin Krawczyk escribió:The first \{.+\} match starts at the first { and ends at the last },> Hi list,
>
> I'm trying to use regexp_replace to get rid of all occurrences of
> certain sub strings from my string.
> What I'm doing is:
>
> SELECT regexp_replace('F0301 305-149-101-0 F0302 {x1} 12W47 0635H
> {tt}{POL23423423}', E'\{.+\}', '', 'g')
>
> so get rid of whatever is between { } along with these,
>
> but it results in:
> 'F0301 305-149-101-0 F0302 '
>
> how do I get it to be:
> 'F0301 305-149-101-0 F0302 12W47 0635H'
>
> ??
>
> as I understood the docs, the g flag "specifies replacement of each
> matching substring rather than only the first one"
eating the {s and }s in the middle. So there's only one match and that's
what's removed.You need a non-greedy quantifier. Try
> what am I missing ?
SELECT regexp_replace('F0301 305-149-101-0 F0302 {x1} 12W47 0635H {tt}{POL23423423}', E'\{.+?\}', '', 'g')
--
Álvaro Herrera http://www.2ndQuadrant.com/
PostgreSQL Development, 24x7 Support, Training & Services
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