Re: problem with regexp_matches in nested funcion
От | Isaac Marco Blancas |
---|---|
Тема | Re: problem with regexp_matches in nested funcion |
Дата | |
Msg-id | CAA2CX-1bOSEe4+FgS=S2a4NCCyVq8eLDt7XtGidcrpZxSPR3-A@mail.gmail.com обсуждение исходный текст |
Ответ на | problem with regexp_matches in nested funcion ("David G. Johnston" <david.g.johnston@gmail.com>) |
Список | pgsql-sql |
Thank you for your feedback.
Finally I have solved nesting the regexp_matches functions inside sub-select and selecting the first row with [1]select message as before,
replace(message,
(select regexp_matches(message,'\\$\\$.*?\\{tabular\\}.*?\\$\\$','n'))[1],
replace((select regexp_matches(message,'\\$\\$.*?\\{tabular\\}.*?\\$\\$','n'))[1],'{tabular}','{array}')) as later
from mdl_forum_posts
where message ~ '\\$\\$.*?\\{tabular\\}.*?\\$\\$';
2015-09-22 14:36 GMT+02:00 David G. Johnston <david.g.johnston@gmail.com>:
On Tuesday, September 22, 2015, Isaac Marco Blancas <isaac.marco@udima.es> wrote:I get this error:When I run this:
ERROR: functions and operators can take at most one set argument
SQL state: 0A000
select message as before,
replace(message,
array_to_string(regexp_matches(message,'\\$\\$.*?\\{tabular\\}.*?\\$\\$'), '#'),
replace(array_to_string(regexp_matches(message,'\\$\\$.*?\\{tabular\\}.*?\\$\\$'), '#'),'tabular','array')) as later
from mdl_forum_posts
where message ~ '\\$\\$.*?\\{tabular\\}.*?\\$\\$';I know the problem is in the second array_to_string. Some idea?Regexp_matches returns a set of arrays, not one-and-only-one. You need to decide on a strategy to pass only single rows into the array and replace functions. I personally wrote a regexp_matches_single function that wraps the and use that in almost all situations. It wraps the Mai. Function but is defined to always return a single array.David J.
--
Isaac Marco Blancas
Universidad a Distancia de Madrid (UDIMA)
902 02 00 03
Universidad a Distancia de Madrid (UDIMA)
902 02 00 03
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