Re: Regex match not back-referencing in function
От | Thom Brown |
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Тема | Re: Regex match not back-referencing in function |
Дата | |
Msg-id | CAA-aLv4aj07zyP-4vfyo=urnX+qyEykf8CBi=kFyULL6wKD7Rw@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Regex match not back-referencing in function (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-general |
On 12 February 2012 18:49, Tom Lane <tgl@sss.pgh.pa.us> wrote: > Thom Brown <thom@linux.com> writes: >> What am I missing? > > I might be more confused than you, but I think you're supposing that > the result of ascii(E'\\1') has something to do with the match that > the surrounding regexp_replace function will find, later on when it > gets executed. The actual arguments seen by regexp_replace are > > regression=# select E'Hello & goodbye ',E'([&])','' || > ascii(E'\\1') || E';\\1'; > ?column? | ?column? | ?column? > ------------------+----------+---------- > Hello & goodbye | ([&]) | \\1 > (1 row) > > and given that, the result looks perfectly fine to me. > > If there's a bug here, it's that ascii() ignores additional bytes in its > input instead of throwing an error for a string with more than one > character. But I believe we've discussed that in the past and decided > not to change it. Okay, in that case I made the wrong assumptions about order of resolution. Thanks -- Thom
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