Re: Directly embedding a psql SET variable inside another string?
От | Adam Scott |
---|---|
Тема | Re: Directly embedding a psql SET variable inside another string? |
Дата | |
Msg-id | CA+s62-OBC_VQihE5RMW6_rYyoiH_HCbb6pbPS=+1DwaYOd8Adw@mail.gmail.com обсуждение исходный текст |
Ответ на | Directly embedding a psql SET variable inside another string? (Ron <ronljohnsonjr@gmail.com>) |
Ответы |
Re: Directly embedding a psql SET variable inside another string?
Re: Directly embedding a psql SET variable inside another string? |
Список | pgsql-general |
Do you mean like this?
postgres=# \set v_embed %:v_ssn%
postgres=# \echo :v_embed
%345%
postgres=# SELECT * FROM employee WHERE ssn LIKE :'v_embed';
ssn | name
-----------+----------
123456789 | John Doe
(1 row)
postgres=# \echo :v_embed
%345%
postgres=# SELECT * FROM employee WHERE ssn LIKE :'v_embed';
ssn | name
-----------+----------
123456789 | John Doe
(1 row)
On Fri, Jan 13, 2023 at 8:12 AM Ron <ronljohnsonjr@gmail.com> wrote:
Pg 12
I need to pass a \set variable (in this example named v_ssn) into a LIKE string. A two-stage process (building v_like from v_ssn, and then using v_like in the LIKE string) works, and is fine when executing an sql script, but not so good is there any way to directly embed v_ssn in another string?
test=# \set v_ssn 345
test=# \echo :v_ssn
345
test=# \set v_like %:v_ssn%
test=# \echo :v_like
%345%
test=# SELECT * FROM employee WHERE ssn LIKE :'v_like';
ssn | name | ssn_int
-----------+----------+-----------
123456789 | John Doe | 123456789
(1 row)
As expected, this fails:
postgres=# SELECT * FROM employee WHERE ssn LIKE :'%v_ssn%';
ERROR: syntax error at or near ":"
LINE 1: SELECT * FROM employee WHERE ssn LIKE :'%v_ssn%';--
Born in Arizona, moved to Babylonia.
В списке pgsql-general по дате отправления: