Re: psycopg3, prepared statements
От | Daniele Varrazzo |
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Тема | Re: psycopg3, prepared statements |
Дата | |
Msg-id | CA+mi_8aoK_wbSQimZ4WHHXZT2YTBPfxLj9Zsbfbx8o=gfBWyaQ@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: psycopg3, prepared statements (Vladimir Ryabtsev <greatvovan@gmail.com>) |
Ответы |
Re: psycopg3, prepared statements
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Список | psycopg |
On Wed, 23 Dec 2020 at 23:23, Vladimir Ryabtsev <greatvovan@gmail.com> wrote: > > Cause (query, types) can give more combinations than (query,)? Yes, that's the reason In [1]: import psycopg3 In [2]: cnn = psycopg3.connect() In [3]: cnn.prepare_threshold = 2 In [4]: cnn.execute("select 1 + %s", [1]).fetchone() Out[4]: (2,) In [5]: cnn.execute("select 1 + %s", [None]).fetchone() Out[5]: (None,) In [7]: cnn.execute("select 1 + %s", [2]).fetchone() Out[7]: (3,) After 3 times the expression should have been prepared, but the tally has been spread in two values (0 is unknown oid, 20 is int oid). In [8]: cnn._prepared_statements Out[8]: OrderedDict([((b'select 1 + $1', (0,)), 1), ((b'select 1 + $1', (20,)), 2)]) In [9]: cnn.execute("select 1 + %s", [3]).fetchone() Out[9]: (4,) However, when either key passes the threshold, eventually preparation happens. In [10]: cnn._prepared_statements Out[10]: OrderedDict([((b'select 1 + $1', (0,)), 1), ((b'select 1 + $1', (20,)), b'_pg3_0')]) _pg3_0 is the name under which that combination of query and types is now prepared (it is local per session). -- Daniele
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