Re: [SQL] simple "select / if found" isn't
От | Jan Otto |
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Тема | Re: [SQL] simple "select / if found" isn't |
Дата | |
Msg-id | C9BFAD75-EB0B-4107-A6D9-31ED34D7AF6D@me.com обсуждение исходный текст |
Ответы |
Re: [SQL] simple "select / if found" isn't
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Список | pgsql-sql |
hi gary, > On 16 Dec 2016, at 12:02, Gary Stainburn <gary.stainburn@ringways.co.uk> wrote: > > I'm creating a simple function that must have been done millions of times > before, but I can't get it to work. In this case, I'm checking a user ID and > password against previously used passwords: > > All I want to do is return 'found' based on the select but I can't get it to > work. > > If I run > > select 1 from user_previous_passwords > where u_id=25 and > crypt('MyPaSSword',u_previous_password) = u_previous_password; > > then it returns the matching row(s) > > If I run my function > > create or replace function check_previous_passwords (ID int4, PASS varchar) > returns boolean as $$ > DECLARE > UID int4; > BEGIN > return exists(select 1 from user_previous_passwords > where u_id=ID and crypt(PASS,u_previous_password) = PASS); return exists(select 1 from user_previous_passwords where u_id=ID and crypt(PASS,u_previous_password) = u_previous_password); > END; > $$ LANGUAGE plpgsql; regards, jan
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