Re: How do I remove selected words from text field?

Osvaldo Kussama wrote:
> 2010/7/1 Frank Bax <fbax@sympatico.ca>:
>> Create some tables; then add some data:
>>
>> create table t1 (i int, v varchar);
>> insert into t1 values(1,'A B C D');
>> insert into t1 values(2,'B D E F');
>> insert into t1 values(3,'G H I J');
>> insert into t1 values(4,'E');
>> create table t2 (q varchar, z varchar);
>> insert into t2 values('A','vowel');
>> insert into t2 values('B','consonant');
>> insert into t2 values('E','vowel');
>> insert into t2 values('K','consonant');
>>
>> I am trying to write a function which will:
>> * split the argument into "words" (separated by blanks);
>> * remove words that meet a certain condition in another table
>>  (in this example 'vowel');
>> * reassemble "words" into a string;
>> * return the result
>> This query does that job (Thanks Osvaldo):
>>
>> SELECT i, array_to_string(array_agg(word), ' ') "new-v" FROM
>> (SELECT * FROM (SELECT i, regexp_split_to_table(v, E'\\s+') AS word FROM t1)
>> bar
>> LEFT OUTER JOIN t2 ON (bar.word=t2.q)
>> WHERE z IS DISTINCT FROM 'vowel') foo
>> GROUP BY i;
>>
>>  i |  new-v
>> ---+---------
>>  1 | B C D
>>  3 | G H I J
>>  2 | B D F
>> (3 rows)
>>
>>
>> When I try to create a function to do the same thing; it only works for
>> (4,'E') and not the other tuples.
>>
>> CREATE OR REPLACE FUNCTION notvowel(text) RETURNS text AS $$
>>  SELECT array_to_string(array_agg(word),' ') FROM
>>  (SELECT * FROM (SELECT regexp_split_to_table($1, E'\s+') AS word) bar
> 
> Use E'\\s+' or E'[[:space:]]+' in regexp_split_to_table function.


Both of these produce incorrect results...
  i |    v    | notvowel
---+---------+----------  1 | A B C D | C  2 | B D E F | B  3 | G H I J | G  4 | E       | (4 rows)