a query with = ALL
От | Jaime Casanova |
---|---|
Тема | a query with = ALL |
Дата | |
Msg-id | BAY8-F81FaO0dlJMm530007a405@hotmail.com обсуждение исходный текст |
Ответы |
Re: a query with = ALL
|
Список | pgsql-sql |
Hi all, some more info a think can be useful to probe there is somting wrong. I pointed that the query select cur_paralelo from rec_m_cuadropagos WHERE ent_codigo = 1 AND sec_codigo = 1 AND ani_codigo = '2004-2005' AND cic_codigo = 1 AND esp_codigo = 0 AND cur_codigo = 1 intersect SELECT cur_paralelo FROM aca_t_curso WHERE ent_codigo = 1 AND sec_codigo = 1 AND ani_codigo = '2004-2005' AND cic_codigo = 1 AND esp_codigo = 0 AND cur_codigo = 1 brings 'A ', 'B ', 'C ' well when i cHange the real query SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor, CPA.cpa_fechavencimiento FROM rec_m_cuadropagos CPA, rec_m_rubro RUB WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo AND CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo = '2004-2005' AND CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1 AND CPA.cur_paralelo = 'A ' then it brings the result that it would but when i do the same with =ALL it doesn't work thanx in advance, Jaime Casanova _________________________________________________________________ MSN 8 helps eliminate e-mail viruses. Get 2 months FREE*. http://join.msn.com/?page=features/virus
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