Re: query with =ALL
От | Jaime Casanova |
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Тема | Re: query with =ALL |
Дата | |
Msg-id | BAY8-F43IO1PH5phq9d0003307c@hotmail.com обсуждение исходный текст |
Ответ на | query with =ALL ("Jaime Casanova" <el_vigia_ec@hotmail.com>) |
Ответы |
Re: query with =ALL
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Список | pgsql-sql |
Hi all, > > AND > > CPA.cur_paralelo = ALL (SELECT cur_paralelo FROM aca_t_curso ...) > >Wait a second ... we are all overthinking the problem. The subselect >returns three *different* values. It is not possible for any >CPA.cur_paralelo values to be simultaneously equal to all three. >So this test certainly fails at every row of CPA. > >Perhaps you meant "= ANY"? Not really becuase ANY has the same efect that IN and what i want is all the results that are equal in all the rows in any of the cur_paralelo values. But must be in all the cur_paralelo or nothing. thanx in advance, Jaime Casanova _________________________________________________________________ MSN 8 helps eliminate e-mail viruses. Get 2 months FREE*. http://join.msn.com/?page=features/virus
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