Re: Extract from date field
От | Thom Brown |
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Тема | Re: Extract from date field |
Дата | |
Msg-id | BANLkTinkkOpV76K3bwyRYSczAqD0WkGLng@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Extract from date field (James David Smith <james.david.smith@gmail.com>) |
Ответы |
Re: Extract from date field
Re: Extract from date field |
Список | pgsql-novice |
On 17 June 2011 20:12, James David Smith <james.david.smith@gmail.com> wrote: > Hey, > > I realise it's probably poor form to reply to your own question, but I > thought I'd just say I've managed to do this! Well, question 2 anyway. > To extract a DAY from a date field, and keep a leading zero, I have > used the 'lpad' function like so: > > SELECT lpad (cast((EXTRACT(DAY from timestamp '2010-01-01')) as > varchar), 2, '0') > > Except that in my query it looks like this: > > (SELECT lpad (cast((EXTRACT(DAY from date_of_incident)) as varchar), 2, '0')) > > I thought I'd post this incase it's off use to anyone else. > > Just need to figure out how to convert it all to a integer now... Ah, I believe I've replied to this on Twitter, but I'll post here too. You can use the very handy to_char function to convert your date into a formatted string. (see http://www.postgresql.org/docs/9.0/static/functions-formatting.html ) So you'd end up with: ALTER TABLE camdengps2 ADD COLUMN camdencrimes_link varchar; UPDATE camdengps2 SET camdencrimes_link=(to_char(date_time, 'DDMMYYYY') || incident)::int Hope that solves it for you. -- Thom Brown Twitter: @darkixion IRC (freenode): dark_ixion Registered Linux user: #516935 EnterpriseDB UK: http://www.enterprisedb.com The Enterprise PostgreSQL Company
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