Automating PostgreSql table partition using triggers
От | Amitabh Kant |
---|---|
Тема | Automating PostgreSql table partition using triggers |
Дата | |
Msg-id | AANLkTimLnBoEeBmFJHEWc1vQZuvPPsp920JWyQK8CABn@mail.gmail.com обсуждение исходный текст |
Ответы |
Re: Automating PostgreSql table partition using triggers
Re: Automating PostgreSql table partition using triggers |
Список | pgsql-sql |
Hi<br /><br />I am trying to write a function which is being called from a trigger used for partitioning a large table. Thepartitioning is to happen based on an integer field (testing_id). A simplified structure of what I am trying to do iswritten below.<br /><br />Create Table tbltesting(<br /> testing_id int not null,<br /> testing_name character varying(255));<br/><br />Create table tbltesting1(check(testing_id = 1)) inherits(tbltesting);<br />Create table tbltesting2(check(testing_id= 2)) inherits(tbltesting);<br /><br />CREATE OR REPLACE FUNCTION partition_insert_trigger()<br/>RETURNS TRIGGER AS $$<br />DECLARE id integer ;<br />BEGIN<br /> id := NEW.testing_id;<br /> <br /> INSERT INTO tbltesting'||id||' VALUES (NEW.*); //Problem line, not sure what syntaxto use here<br /><br /> RETURN NULL;<br />END;<br />$$<br />LANGUAGE plpgsql;<br /><br /><br />CREATE TRIGGER partition_trigger<br/> BEFORE INSERT ON tbltesting<br /> FOR EACH ROW EXECUTE PROCEDURE partition_insert_trigger();<br/><br />Creating tables or child tables is not a problem and the trigger works fine if thefunction has static definitions. What I am trying to achieve is use the new testing_id to create a table name for usein the insert statement. If I am able to use the variable in the table name, I would not have to re-declare the functioneach time with modified conditions for each separate testing_id.<br /><br /><br />With regards<br /><br />Amitabh<br/><br />
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