Re: Finding rank of a single record

And:

pref=> select * from (
        select u.id,
        u.first_name,
        u.city,
        m.money,
        rank() over (order by money desc)
        from pref_users u, pref_money m where
        m.yw=to_char(current_timestamp, 'YYYY-IW')
) ar
where ar.id='OK138239987797';


works, but delivers 800 different ranks:

       id       | first_name |    city     | money |  rank
----------------+------------+-------------+-------+---------
 OK138239987797 | Иван       | Новосибирск |  2169 |       1
 OK138239987797 | Иван       | Новосибирск |  1955 |    3479
 OK138239987797 | Иван       | Новосибирск |  1948 |    6957
 OK138239987797 | Иван       | Новосибирск |  1060 |   10435
 OK138239987797 | Иван       | Новосибирск |  1034 |   13913
 OK138239987797 | Иван       | Новосибирск |  1012 |   17391
 OK138239987797 | Иван       | Новосибирск |   929 |   20869