Re: plpgsql out parameter with select into
От | Sergey Konoplev |
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Тема | Re: plpgsql out parameter with select into |
Дата | |
Msg-id | AANLkTi=YT1cYTeu0JbN_0ZYBjN-jyrA6fpRDuQcX95xN@mail.gmail.com обсуждение исходный текст |
Ответ на | plpgsql out parameter with select into (Horváth Imre <horvath.imre@blemidon.hu>) |
Ответы |
Re: plpgsql out parameter with select into
Re: plpgsql out parameter with select into |
Список | pgsql-sql |
Hi, SELECT column_name INTO var_name FROM ... 2010/8/17 Horváth Imre <horvath.imre@blemidon.hu>: > Hi! > > My question is, how can I get the out parameter from a function with > SELECT INTO by name? > I mean: > > create function testfunc1(OUT _status integer) returns integer as > $BODY$ > _status := 0; > $BODY$ > language plpgsql; > > create function testfunc2() as > declare > status integer; > $BODY$ > select into status * from testfunc1(); > $BODY$ > language plpgsql; > > create function testfunc3() as > declare > status integer; > $BODY$ > select into status _status from testfunc1(); > $BODY$ > language plpgsql; > > testfunc2 works, testfunc3 not. > > Thanks in advance: > Imre Horvath > > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql > -- Sergey Konoplev Blog: http://gray-hemp.blogspot.com / Linkedin: http://ru.linkedin.com/in/grayhemp / JID/GTalk: gray.ru@gmail.com / Skype: gray-hemp / ICQ: 29353802
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