Re: Implementing replace function
От | Pavel Stehule |
---|---|
Тема | Re: Implementing replace function |
Дата | |
Msg-id | AANLkTi=E-Hw8t5soLJ2c22OOrw_Sdb1Dd84QFOB3Sfvy@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Implementing replace function (Dmitriy Igrishin <dmitigr@gmail.com>) |
Список | pgsql-general |
2010/10/31 Dmitriy Igrishin <dmitigr@gmail.com>: > Okay, Pavel, will wait for 9.1 :-) > > It is a common case - insert new row if it cannot be updated. you can find (probably) MERGE statement in 9.1. Pavel > > 2010/10/31 Pavel Stehule <pavel.stehule@gmail.com> >> >> Hello >> >> 2010/10/31 Dmitriy Igrishin <dmitigr@gmail.com>: >> > Hey Alexander, Pavel >> > >> > The solution like below should works IMO, but it does not. >> > insert into pref_users(id, first_name, last_name, >> > female, avatar, city, last_ip) >> > select $1, $2, $3, $4, $5, $6, $7 >> > where not exists >> > (update pref_users set first_name = $2, >> > last_name = $3, >> > female = $4, >> > avatar = $5, >> > city = $6, >> > last_ip = $7 >> > where id = $1 >> > returning id); >> > >> > BTW, I don't understand why it not possible to write query like this: >> > SELECT id FROM (UPDATE test SET nm = 'dima' WHERE id = 1 RETURNING id) >> > AS >> > foo; >> > According to the doc (of UPDATE command) "The syntax of the RETURNING >> > list >> > is identical to >> > that of the output list of SELECT). >> > With this syntax, the OPs goal can be implemented in SQL.. >> > >> >> UPDATE RETURNING isn't subselect - so you can't do SELECT FROM (UPDATE >> RETURNING) directly. It's possible with wrapping to sql function. >> >> In next pg version 9.1 you can do it via Updatable Common Table >> Expression, but it isn't possible in older version. >> >> Regards >> >> Pavel Stehule >> >> > -- >> > // Dmitriy. >> > >> > >> > > > > > -- > // Dmitriy. > > >
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