Re: simple function index question
От | Igor Neyman |
---|---|
Тема | Re: simple function index question |
Дата | |
Msg-id | A76B25F2823E954C9E45E32FA49D70ECCD680659@mail.corp.perceptron.com обсуждение исходный текст |
Ответ на | simple function index question (Michael Moore <michaeljmoore@gmail.com>) |
Список | pgsql-sql |
From: pgsql-sql-owner@postgresql.org [mailto:pgsql-sql-owner@postgresql.org] On Behalf Of Michael Moore
Sent: Tuesday, March 22, 2016 8:24 PM
To: postgres list <pgsql-sql@postgresql.org>
Subject: [SQL] simple function index question
This:
CREATE INDEX TX_QSET_DIR_MAP_PRI_URI_TYP_UK
ON tx_question_set_dir_map
USING btree
((
CASE
WHEN uri_type = 201900 then
(question_set2tx_question_set ,uri_type, null)
ELSE
(question_set2tx_question_set ,uri_type, question_set_dir_map_key)
END))
TABLESPACE qsn_indx_ol;
results in
ERROR: column "" has pseudo-type record
********** Error **********
ERROR: column "" has pseudo-type record
SQL state: 42P16
Hopefully it is clear what I am attempting to do here. How do I make this happen?
Try casting NULL to whatever type question_set_dirmap_key is.
Sai it is varchar, then:
……………………………………………..
WHEN uri_type = 201900 then
(question_set2tx_question_set ,uri_type, null::varchar)
……………………………………………………………….
Regards,
Igor Neyman
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