FW: [SQL] OUTER JOINS
От | Michael J Davis |
---|---|
Тема | FW: [SQL] OUTER JOINS |
Дата | |
Msg-id | 93C04F1F5173D211A27900105AA8FCFC1453DB@lambic.prevuenet.com обсуждение исходный текст |
Список | pgsql-sql |
*= and =* are Oracle syntax for outer joins. -----Original Message-----From: Dan Janowski [SMTP:danj@3skel.com] <mailto:[SMTP:danj@3skel.com]> Sent: Monday, April 19, 1999 7:27 AMTo: J_Shevland@TurnAround.com.au <mailto:J_Shevland@TurnAround.com.au> Cc: pgsql-sql@postgreSQL.org <mailto:pgsql-sql@postgreSQL.org> Subject: Re: [SQL]OUTER JOINS Thanks for giving it a stab. Looking at the availableoperators,there is no =* or *= ops available. Although I am curiouswhereitcomes from. Dan Joe Shevland wrote:> ... > select t1.value from table_one t1, table_two t2 where t1.key = t2.key;> > So this would be a straight LEFT join in my understanding. Now, I'm> venturing beyond my experience with PostgreSQL here, but you may be able> to use the associated SQL syntaxes:> > select ... where t1.key *= t2.key> select ... where t1.key =* t2.key> ...>>Dan Janowski wrote:> >> > I've looked through the docs and mail lists but I am coming> > up short on references forLEFT/RIGHT/FULL OUTER JOIN> > avalability> > or functional workarounds. It seems that PostgreSQL does> > not have it.>>> > Any recommendations on how to aproximate the functionality?> >> > As a curiosity, is there a problem with supportingthese> > OUTER joins or is it merely on the list?> > --Dan Janowski danj@3skel.com <mailto:danj@3skel.com> Triskelion Systems,Inc. Bronx, NY
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