RE: [SQL] OUTER JOINS
От | Michael J Davis |
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Тема | RE: [SQL] OUTER JOINS |
Дата | |
Msg-id | 93C04F1F5173D211A27900105AA8FCFC1453D8@lambic.prevuenet.com обсуждение исходный текст |
Ответ на | [SQL] OUTER JOINS (Dan Janowski <danj@3skel.com>) |
Список | pgsql-sql |
*= and =* are Oracle syntax for outer joins. > -----Original Message----- > From: Dan Janowski [SMTP:danj@3skel.com] > Sent: Monday, April 19, 1999 7:27 AM > To: J_Shevland@TurnAround.com.au > Cc: pgsql-sql@postgreSQL.org > Subject: Re: [SQL] OUTER JOINS > > Thanks for giving it a stab. Looking at the available > operators, > there is no =* or *= ops available. Although I am curious > where it > comes from. > > Dan > > > Joe Shevland wrote: > > ... > > select t1.value from table_one t1, table_two t2 where t1.key = t2.key; > > > > So this would be a straight LEFT join in my understanding. Now, I'm > > venturing beyond my experience with PostgreSQL here, but you may be able > > to use the associated SQL syntaxes: > > > > select ... where t1.key *= t2.key > > select ... where t1.key =* t2.key > > ... > > > > Dan Janowski wrote: > > > > > > I've looked through the docs and mail lists but I am coming > > > up short on references for LEFT/RIGHT/FULL OUTER JOIN > > > avalability > > > or functional workarounds. It seems that PostgreSQL does > > > not have it. > > > > > > Any recommendations on how to aproximate the functionality? > > > > > > As a curiosity, is there a problem with supporting these > > > OUTER joins or is it merely on the list? > > > > > -- > Dan Janowski danj@3skel.com Triskelion Systems, > Inc. Bronx, NY
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