Re: SELECT duplicates in a table
От | vhikida@inreach.com |
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Тема | Re: SELECT duplicates in a table |
Дата | |
Msg-id | 9211.146.74.1.99.1101146160.squirrel@146.74.1.99 обсуждение исходный текст |
Ответ на | SELECT duplicates in a table ("Kall, Bruce A." <kall@mayo.edu>) |
Ответы |
Re: SELECT duplicates in a table
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Список | pgsql-general |
Try SELECT * FROM mytable WHERE (identification_number,date_of_birth) IN (SELECT identification_number , date_of_birth FROM mytable m2 GROUP BY identification_number,data_of_birth HAVING COUNT(*) > 1 ) There are other ways of doing it, perhaps more efficient. Vincent > I've look for a solution to this, but have only been able to find > solutions to delete duplicate entries in a table by deleting entries not > returned by SELECT DISTINCT. > > What sql should I use to SELECT entries in a table that have two > particular column values that match? > > For example, my_table has > name, phone number, identification_number, zip code, date of birth, and > city > > I want to SELECT rows from this table that have the same values in > identification and date of birth (duplicates) so I can have the user > look at them in order to figure out which one to delete. > > I tried something like: > > $db_sql = "SELECT * FROM my_table GROUP BY identification_number > HAVING count(date_of_birth) > 1 ORDER BY name" > > but that doesn't seem to work. > > Thanks, > Bruce > > > ---------------------------(end of broadcast)--------------------------- > TIP 6: Have you searched our list archives? > > http://archives.postgresql.org >
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