Re: numeric calculation bug as of 16.2-2
От | Tom Lane |
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Тема | Re: numeric calculation bug as of 16.2-2 |
Дата | |
Msg-id | 915577.1715659935@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: numeric calculation bug as of 16.2-2 (David Rowley <dgrowleyml@gmail.com>) |
Ответы |
Re: numeric calculation bug as of 16.2-2
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Список | pgsql-bugs |
David Rowley <dgrowleyml@gmail.com> writes: > On Tue, 14 May 2024 at 14:53, Huw Rogers <djnz00@gmail.com> wrote: >> test=# select ('170141183460469231731687303715884105727'::numeric / '9223372036854775808'::numeric) * '9223372036854775808'::numeric; >> ?column? >> ----------------------------------------- >> 170141183460469231731687303715884105728 > I don't have enough experience in NUMERIC to tell if this is a bug or > not. It is not. If you think that using numeric (or any other general-purpose arithmetic code) means you'll always get exact answers for every calculation, I have a bridge in Brooklyn I'd like to sell you. The specific problem with the example you give is that you're using fractional-power-of-2 numbers and expecting them to be exactly representable in numeric's base-10 arithmetic. That's not happening. Amusingly, type float8 (which is binary at bottom) can represent such numbers exactly, so that this works: =# select ((2^127)/(2^63))*(2^63) = (2^127); ?column? ---------- t (Use pg_typeof to verify that the subexpressions are type float8.) Nonetheless, float8 has a well-deserved reputation for being imprecise with the decimal fractions that people commonly work with. That's just the opposite side of the same coin: conversion between the two bases is inexact, unless you are willing to work with an unlimited number of fractional digits, which in practice nobody is. BTW, just as a point of order, I cannot reproduce your complaint: =# select ((2^127::numeric)/(2^63::numeric))*(2^63::numeric) = (2^127::numeric); ?column? ---------- t (1 row) =# select (2^127::numeric), (2^63::numeric); ?column? | ?column? -----------------------------------------+--------------------- 170141183460469231731687303715884105728 | 9223372036854775808 (1 row) =# select (170141183460469231731687303715884105728/9223372036854775808)*9223372036854775808 = 170141183460469231731687303715884105728; ?column? ---------- t (1 row) I don't know where you got '170141183460469231731687303715884105727' from, but that seems off-by-one. This doesn't invalidate my larger point though. regards, tom lane
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