Re: Selecting latest value II
От | Carl van Tast |
---|---|
Тема | Re: Selecting latest value II |
Дата | |
Msg-id | 90hkqtoul1cnb9pqpn47i7544j9oik9s3d@4ax.com обсуждение исходный текст |
Ответ на | Re: Selecting latest value II (Haller Christoph <ch@rodos.fzk.de>) |
Список | pgsql-sql |
Hi, Thurstan On Thu, 20 Sep 2001 17:30:46 +0100, "Thurstan R. McDougle" <trmcdougle@my-deja.com> wrote: > [...] >Carl van Tast had 2 good methods as follows > >SELECT userid, val >FROM tbl >WHERE NOT EXISTS (SELECT * FROM tbl AS t2 > WHERE tbl.userid=t2.userid AND t2.ts > tbl.ts); > >or > >SELECT tbl.userid, tbl.val >FROM tbl > INNER JOIN > (SELECT userid, max(ts) AS maxts > FROM tbl > GROUP BY userid) AS t2 > ON (tbl.userid=t2.userid AND tbl.ts=t2.maxts); ... although I like Tom Lane's even better. This one should outperform all others, especially my first one: > SELECT DISTINCT ON (userid) userid, val, ts FROM table > ORDER BY userid, ts DESC; That's the reason I'm here: learning by helping :-) Kind regardsCarl van Tast
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