Re: How to assemble all fields of (any) view into a string?
От | Jim Nasby |
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Тема | Re: How to assemble all fields of (any) view into a string? |
Дата | |
Msg-id | 90ae74a2-da89-a79c-325f-e9234ed5030c@BlueTreble.com обсуждение исходный текст |
Ответ на | Re: How to assemble all fields of (any) view into a string? (Ken Tanzer <ken.tanzer@gmail.com>) |
Ответы |
Re: How to assemble all fields of (any) view into a string?
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Список | pgsql-general |
On 9/7/16 6:07 PM, Ken Tanzer wrote: > ERROR: PL/Python functions cannot accept type record Ugh, yeah... that won't work. plperl might be able to do it, but I suspect you're going to be stuck pulling the size info out of info_schema or the catalog. Actually, there is a way you could hack this via plpython; pass the row in as text as well as the relation (regclass is good for that). You could then do plpy.execute('SELECT (%::%).*'.format(row_text, relation)); that should give you a dict just like Adrian's example did. It would be nice if there was a function that accepted something with a row descriptor and spit out the details of the descriptor. http://pgxn.org/dist/colnames/doc/colnames.html comes close; if you know much about C at all it shouldn't be hard to add a function to that extension that returned the full details of the row. That and converting the row to JSON would make it relatively easy to accomplish what you want in a plpgsql (or maybe even plsql) function. -- Jim Nasby, Data Architect, Blue Treble Consulting, Austin TX Experts in Analytics, Data Architecture and PostgreSQL Data in Trouble? Get it in Treble! http://BlueTreble.com 855-TREBLE2 (855-873-2532) mobile: 512-569-9461
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