Re: Updating 3-table dataset
От | Moreno Andreo |
---|---|
Тема | Re: Updating 3-table dataset |
Дата | |
Msg-id | 8fe49799-a2a3-ff36-dbca-432363f9a26b@evolu-s.it обсуждение исходный текст |
Ответ на | Re: Updating 3-table dataset (Luca Ferrari <fluca1978@gmail.com>) |
Список | pgsql-general |
Il 09/08/19 16:50, Luca Ferrari ha scritto: > On Fri, Aug 9, 2019 at 2:29 PM Moreno Andreo <moreno.andreo@evolu-s.it> wrote: >> Hi all, >> I don't know if that's the heat burning my brain but I can't find a >> solution to what seemed a simple operation to me. >> >> I have 3 tables >> create table t_all >> { >> id uuid, >> ref_id uuid (FK to t_ana.id) >> }; >> create table t_ana >> { >> id uuid, >> code text >> }; >> create table t_app >> { >> id uuid, >> code text (subset of t_ana.code) >> } >> I need to update t_all set t_all.id = t_app.id having t_ana.code in >> t_app.code (I wrote it in some kind of meta-sql but I hope it's clear) >> I tried to create a view but I need an INSTEAD OF trigger, since it >> spreads among 3 tables so I hope there's some faster path to achieve the >> solution.... >> > Not sure I got what you need, and I've not tested, but something like > the following: > > WITH must_update AS ( > SELECT app.id AS app_id, ana.id AS ana_id > FROM t_app app, t_ana ana > WHERE app.code = ana.code > ) > > UPDATE t_all > SET id = ( SELECT app_id FROM must_update WHERE ref_id = must_update.ana_id ); > > I've written the CTE because it is a little clearer in my mind, but > you can push down as a subquery of course. Thanks Luca, that's the idea I needed... now some small trimming and I think I'll be there (just for the logs... the UPDATE statement needs a WHERE clause, otherwise it will NULL the id field in all rows where ref_id is not present in must_update :-) ) I owe you a beer :-) Cheers Moreno. > > Luca >
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