Re: selecting the record before the last one
От | greg@turnstep.com |
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Тема | Re: selecting the record before the last one |
Дата | |
Msg-id | 7a453c6139cf0bac3d55f4bae007177d@biglumber.com обсуждение исходный текст |
Ответ на | selecting the record before the last one (MT <m_tessier@sympatico.ca>) |
Список | pgsql-general |
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 The quick answer is no: you cannot specifically match a certain column and not match a certain column at the same time. You are already creating the SQL statements manually, so why not just create different ones for each situation? if (historical search) { $query = "SELECT * FROM difference WHERE clientid = $CLIENTID ORDER BY cartid ASC LIMIT 1"; } else { $query = "SELECT * FROM difference WHERE clientid = $CLIENTID AND cartid = $CARTID"; } More importantly, however, there seems to be a fatal flaw in your process: > By adding the "ORDER BY cartid ASC LIMIT 1" to the sql statement, the user > gets the most recent credit amount for that customer entered into the > system. That is, the credit amount created by the previous invoice. > ...when the user is creating an invoice, that invoice's cartid (which is > a random number) is already entered into the system, If "cartid" is a random number, 'ORDER BY cartid ASC' is not going to do you any good. - -- Greg Sabino Mullane greg@turnstep.com PGP Key: 0x14964AC8 200306261048 -----BEGIN PGP SIGNATURE----- Comment: http://www.turnstep.com/pgp.html iD8DBQE++wlmvJuQZxSWSsgRAizgAJ9tXUD9i3fhbhPQMw7V9z7AXbSwuQCgkfHg hsq/uuge0mxcyoj9WqAYkTY= =0WLM -----END PGP SIGNATURE-----
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