Re: multiple rows by date using count(*)
От | Alban Hertroys |
---|---|
Тема | Re: multiple rows by date using count(*) |
Дата | |
Msg-id | 7D78D05F-B9B6-4648-9D4F-A0FCE8B576D7@solfertje.student.utwente.nl обсуждение исходный текст |
Ответ на | multiple rows by date using count(*) (Shad Keene <shadkeene@hotmail.com>) |
Список | pgsql-general |
On Jul 5, 2009, at 5:20 AM, Shad Keene wrote: > PRB | RBL | SAC | SFO | > June 1 2 | 4 | 5 | 2 | > June 2 1 | 3 | 4 | 0 | > June 3 0 | 2 | 1 | 2 | > > So far, here's the query I'm using to display one row of all items > with certain keywords, but I've failed at trying to make multiple > rows by date. > > Here's the query I'm using so far: > select (select count (*) from zoa_pireps where raw_text like '%RBL > %') as RBL, (select count(*) from zoa_pireps where raw_text like > '%RBL%') as PRB; I think you're looking for something like this: select date, sum(case when raw_text like '%RBL%' then 1 else 0 end) as RBL, sum(case when raw_text like '%PRB%' then 1 else 0 end) as PRB from zoa_pireps group by date. It's probably a lot more readable if you wrap those expressions in an immutable function. Alban Hertroys -- If you can't see the forest for the trees, cut the trees and you'll see there is no forest. !DSPAM:737,4a5071bf759151100320669!
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