Re: "Copy from" omit source columns?
От | Richard Broersma Jr |
---|---|
Тема | Re: "Copy from" omit source columns? |
Дата | |
Msg-id | 737014.20604.qm@web31801.mail.mud.yahoo.com обсуждение исходный текст |
Ответ на | "Copy from" omit source columns? (Steve Midgley <public@misuse.org>) |
Список | pgsql-sql |
> (I already fear the answer to my question is "no..") :) > I am using the 'COPY FROM' SQL command (not psql \copy) to move data > into a table from a CSV file. The source data are suitable for import > EXCEPT there are extraneous columns of data in the source file. In > essence, my table schema is: > id, col1, col2, col4 > My source file schema is: > col1,col2,col3,col4 > I'm curious if there is any way to tell "COPY" to ignore the third > column of data? Basically I'd like to write something along the lines > of: > copy import (col1,col2,\n,col4) > from 'c:/dev/import/source/test.csv' > with CSV HEADER > Note "\n" would indicate there there is a column in the source that > should simply be ignored during the import. Of course, I tried this > syntax and it didn't work. Perhaps there is another way of indicating > that there is a "null column" in the source file that should be skipped > during import? > Any assistance in solving this problem (without having to change the > source file) would be greatly appreciated. If I have to change the > source file, I will, but it would greatly simplify things if I didn't > have to.. I am not to familiar with using copy, so I do not know the eligant solution that you are looking for. But the brute-force method would be to: 1) push all your data into a temp table 2) validate it 3) push the data of enterest into the destination table. Regards, Richard Broersma Jr.
В списке pgsql-sql по дате отправления: