Re: SQL statement form shell ?
От | czezz |
---|---|
Тема | Re: SQL statement form shell ? |
Дата | |
Msg-id | 6bc90f73.12c57c82.53fee61d.853f@o2.pl обсуждение исходный текст |
Ответ на | Re: SQL statement form shell ? (Scott Whitney <scott@journyx.com>) |
Список | pgsql-admin |
Hi,
I think I got it.
It seems that I need to indicate specific user name and only then the query works.
-bash-4.1$ psql -p 5472 -d fm_db_Server4 -U msuper -c "SELECT * FROM foo2;"
Im new to postgresql but I guess -U (user) also somehow defines tablespace where specific table is created.
Anyway, thank you all for your help and answers.
Cheers,
czezz
Dnia 27 sierpnia 2014 17:30 Scott Whitney <scott@journyx.com> napisał(a):
I think I got it.
It seems that I need to indicate specific user name and only then the query works.
-bash-4.1$ psql -p 5472 -d fm_db_Server4 -U msuper -c "SELECT * FROM foo2;"
Im new to postgresql but I guess -U (user) also somehow defines tablespace where specific table is created.
Anyway, thank you all for your help and answers.
Cheers,
czezz
Dnia 27 sierpnia 2014 17:30 Scott Whitney <scott@journyx.com> napisał(a):
There are a few things I would check.a) psql -p 5472 -d fm_db_Server4b) SELECT * from foo2;c) Do those _2_ statements work separately? That should prove that you're talking to the exact same connection/host/port you expect.d) psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2;So, step a&b succeed, but step d fails?d) psql -p 5472 -d fm_db_Server4e) SELECT * from "foo2";If this doesn't work, "foo2," is not a valid relation. It's case-sensitive or some such. Once you can make the table name work within " " marks, THEN try from the command prompt like:f) psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM \"foo2\" ; "Im trying to execute simple query in shell.
This query works OK in PSQL client:
Server4=# SELECT * FROM foo2;However, for some reason I cannot execute it in shell. I try it like following:-bash-4.1$ psql -p 5472 -d fm_db_Server4 -c "SELECT * FROM foo2;"
ERROR: relation "foo2" does not exist
LINE 1: SELECT * FROM foo2;
^Any ideas what Im doing wrong ?BR,
czezz
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