Re: grouping subsets
От | Oliveiros d'Azevedo Cristina |
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Тема | Re: grouping subsets |
Дата | |
Msg-id | 6FDFC090436D4DA98EBB99D0757B5930@marktestcr.marktest.pt обсуждение исходный текст |
Ответ на | grouping subsets (Rainer Stengele <rainer.stengele@diplan.de>) |
Ответы |
Re: grouping subsets
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Список | pgsql-sql |
Howdy, Rainer. Please advice me, The dates always follow that sequential pattern? Or can be holes on the dates sequence? Best, Oliveiros ----- Original Message ----- From: "Rainer Stengele" <rainer.stengele@diplan.de> To: <pgsql-sql@postgresql.org> Sent: Thursday, July 22, 2010 9:09 AM Subject: [SQL] grouping subsets > Hi, > > having a table similar to > > | 1 | B | [2010-07-15 Do] | > | 1 | B | [2010-07-16 Fr] | > |---+---+-----------------| > | 2 | C | [2010-07-17 Sa] | > | 2 | C | [2010-07-18 So] | > |---+---+-----------------| > | 1 | B | [2010-07-19 Mo] | > | 1 | B | [2010-07-20 Di] | > | 1 | B | [2010-07-21 Mi] | > | 1 | B | [2010-07-22 Do] | > |---+---+-----------------| > | 3 | D | [2010-07-23 Fr] | > > a simple group by gives me: > > | 6 | B | > | 4 | C | > | 3 | D | > > > What I want to get is the values grouped by "subset", where a subset is a > set of rows with identical column until the colum changes. > Is there a way to get > > | 2 | B | > | 4 | C | > | 4 | B | > | 3 | D | > > by SQL only? > > - Rainer > > > > > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql
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