Re: Format intervall as hours/minutes etc
От | Tom Lane |
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Тема | Re: Format intervall as hours/minutes etc |
Дата | |
Msg-id | 6629.1189957316@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: Format intervall as hours/minutes etc (Andreas Joseph Krogh <andreak@officenet.no>) |
Ответы |
Re: Format intervall as hours/minutes etc
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Список | pgsql-sql |
Andreas Joseph Krogh <andreak@officenet.no> writes: > On Sunday 16 September 2007 13:14:27 Andreas Kretschmer wrote: >> You can use extract(epoch, from ...) like this: >> >> test=*# select extract(epoch from '2007-09-22 17:00'::timestamp) - extract >> (epoch from '2000-02-20 18:00'::timestamp); ?column? >> ----------- >> 239407200 >> (1 row) >> >> Now you can calculate the hours and so on. > Yes, this works fine for dates >= 1970, but I'm looking for a more general There's no particular restriction to dates after 1970 there. > solution which takes an arbitrary interval as input. Well, you could subtract the two timestamps and then "extract(epoch ...)" the resulting interval, but I think you'll get the very same answer. [ pokes at it ... ] Hm, we seem to have an overflow problem in the interval-to-epoch code for intervals exceeding 60-some years: regression=# select extract(epoch from '2007-09-22 17:00'::timestamp - '1940-02-20 18:00'::timestamp); date_part ------------2132866800 (1 row) regression=# select extract(epoch from '2007-09-22 17:00'::timestamp - '1930-02-20 18:00'::timestamp); date_part --------------1846567696 (1 row) Looks pretty trivial to fix ... regards, tom lane Index: timestamp.c =================================================================== RCS file: /cvsroot/pgsql/src/backend/utils/adt/timestamp.c,v retrieving revision 1.181 diff -c -r1.181 timestamp.c *** timestamp.c 4 Aug 2007 01:26:54 -0000 1.181 --- timestamp.c 16 Sep 2007 15:33:33 -0000 *************** *** 4395,4403 **** #else result = interval->time; #endif ! result += (DAYS_PER_YEAR * SECS_PER_DAY) * (interval->month / MONTHS_PER_YEAR); result += ((double) DAYS_PER_MONTH* SECS_PER_DAY) * (interval->month % MONTHS_PER_YEAR); ! result += interval->day * SECS_PER_DAY; } else { --- 4395,4403 ---- #else result = interval->time; #endif ! result += ((double) DAYS_PER_YEAR * SECS_PER_DAY) * (interval->month / MONTHS_PER_YEAR); result += ((double)DAYS_PER_MONTH * SECS_PER_DAY) * (interval->month % MONTHS_PER_YEAR); ! result += ((double) SECS_PER_DAY) * interval->day; } else {
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