Re: format integer

On Sun, 2021-01-24 at 09:06 -0700, David G. Johnston wrote:
> 
> On Sunday, January 24, 2021, <ml@ft-c.de> wrote:
> > 
> > I need a integer format with different decimal places 
> > The integer should have 6 diggits. (or 7 or 8)
> >  
> > 
> 
> No, there isn’t a function to apply this convoluted formatting rule
> to non-integer numbers.  You will need to write your own.
> 
> David J.
> 

My idea is
SELECT round(1.2345678912, 5 - least(log(1.2345678912)::int,5) );
SELECT round(12.345678912, 5 - least(log(12.345678912)::int,5) );
SELECT round(123.45678912, 5 - least(log(123.45678912)::int,5) );
SELECT round(1234.5678912, 5 - least(log(1234.5678912)::int,5) );
SELECT round(12345.678912, 5 - least(log(12345.678912)::int,5) );
SELECT round(123456.78912, 5 - least(log(123456.78912)::int,5) );
SELECT round(1234567.8912, 5 - least(log(1234567.8912)::int,5) );
SELECT round(12345678.912, 5 - least(log(12345678.912)::int,5) );
SELECT round(123456789.12, 5 - least(log(123456789.12)::int,5) );

as content for a function 
with arguments (value numeric, diggits int)

Have s.o. a better idea?

Franz