Re: How to \ef a function ?

On 1/8/24 08:26, David Gauthier wrote:
> atletx7-reg017:/home/dgauthie[ 120 ] --> dvdbdev
> Pager usage is off.
> psql (11.5, server 11.3)
> Type "help" for help.
> 
> dvdb=# \df opid.bef_ins_axi_reqs_set_trig;
>                                   List of functions
>   Schema |           Name            | Result data type | Argument data 
> types | Type
> --------+---------------------------+------------------+---------------------+------
>   opid   | bef_ins_axi_reqs_set_trig | trigger          |               
>        | func
> (1 row)
> 
> dvdb=# \ef opid.bef_ins_axi_reqs_set_trig;
> ERROR:  function "opid.bef_ins_axi_reqs_set_trig;" does not exist

Lose the ';'.

It should be:

\ef opid.bef_ins_axi_reqs_set_trig

> dvdb=# \ef opid.bef_ins_axi_reqs_set_trig();
> ERROR:  expected a right parenthesis
> dvdb=#
> 
> So the function exists with \df but not \ef ?
> I get the need to identify the argument list (in case there's >1 with 
> same name, diff arg list), but '()' doesn't work.  Does this have to do 
> with the returned trigger type ?
> 

-- 
Adrian Klaver
adrian.klaver@aklaver.com