Re: how to construct sql
От | Oliveiros |
---|---|
Тема | Re: how to construct sql |
Дата | |
Msg-id | 597755AB8EE8458F92F4B7C6588E5C03@marktestcr.marktest.pt обсуждение исходный текст |
Ответ на | how to construct sql (Wes James <comptekki@gmail.com>) |
Ответы |
Re: how to construct sql
Re: how to construct sql |
Список | pgsql-sql |
Hi, Have you already tried this out? select MAX(page_count_count) - MIN(page_count_count) from page_count group by page_count_pdate. Best, Oliveiros ----- Original Message ----- From: "Wes James" <comptekki@gmail.com> To: <pgsql-sql@postgresql.org> Sent: Wednesday, June 02, 2010 5:48 PM Subject: [SQL] how to construct sql >I am grabbing a printer total and putting it in a table. The > page_count is continuously increasing: > > page_count_count page_count_pdate > 10 2010-05-10 > 20 2010-05-10 > 40 2010-05-11 > 60 2010-05-11 > 80 2010-05-11 > 100 2010-05-12 > 120 2010-05-12 > ..... > > and so on. > > I can do: > > select sum(page_count_count) from page_count group by page_count_pdate. > > and get a total for a day. But this is not the total I want. I want > the total page count for the day. This would mean getting the first > page count of the day and then subtracting that from last page_count > for the day. For 2010-05-11 above it would be > > 80 - 40 = 40 total for the day. Is there a way to do this with sql? > > thx, > > -wes > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql
В списке pgsql-sql по дате отправления: