Re: BUG #18060: Left joining rows using random() function in join condition doesn't work as expected.
От | James Inform |
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Тема | Re: BUG #18060: Left joining rows using random() function in join condition doesn't work as expected. |
Дата | |
Msg-id | 56f6ba9c-baf4-9e6a-78f4-1d22bab587de@pharmapp.de обсуждение исходный текст |
Ответ на | Re: BUG #18060: Left joining rows using random() function in join condition doesn't work as expected. (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-bugs |
That explains the behavior. I thought that the random() was "executed" one time per row, but that is not the case. So, thanks for your quick response. PG Bug reporting form <noreply@postgresql.org> writes: >> -- 2. Execute this query multiple time and you will see results where: >> -- * no rows from link are joined >> -- * extactly one row is joined >> -- * multiple rows are joined >> select * from source left join link on link_id = 1 + (random()*500)::int8 >> order by 1 >> /* >> I would expect always exactly one row to be joined. >> Instead I get 1, none or multiple. > I see no bug here: instead, your expectation is faulty. The > given join condition is unstable by definition, but it would > have to be at least stable to produce the results you expect. > > Formally, the definition of a SQL join is "evaluate the join's ON > condition for each pair of rows in the cross product of the two > input relations, and return the row pair(s) that satisfy the ON". > So with a random() join condition, anywhere from none to all of > the join pairs involving a given LHS row might get returned, > because the random() function will produce a different value > for each join pair. > > You could shove the random() call into a materialized CTE if > the semantics you want are that a single random() result is > used across the entire query. If you want one random() result > to be used for all join pairs involving a given LHS row, but > different ones for different LHS rows, you could probably > make that happen with some hack involving LATERAL. But I'm > too lazy to work it out for you. > > regards, tom lane
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