Interesting. It looks like PostgreSQL is conforming to the
specification (unlike Microsoft SQL or SQL Anywhere). However, it does
not help me with the underlying problem and that is "How do I get the
fractional part of a TIME field via ODBC?".
I have tried SQL_C_TYPE_TIMSTAMP, SQL_C_TYPE_CHAR and
SQL_C_TYPE_DEFAULT. None of these return the fractional part of the
time field. I've also tries SQL_C_TYPE_BINARY and get an error
szSqlState = "07006", *pfNativeError = 14, *pcbErrorMsg = 43,
MessageText = "Received an unsupported type from Postgres."
So how can I get the fractional information?
Note that I do not have any control of the SQL statement. My code needs
to handle any statement and return all information about the query.
Cheers,
Scott
On 05/03/2016 09:03, Adrian Klaver wrote:
> On 03/04/2016 01:20 PM, Scott Ferrett wrote:
>> Here is a screen shot from ODBCTest after Issuing "SELECT ts, t FROM
>> TestTable" and binding an SQL_C_TYPE_TIMESTAMP to each of the two
>> columns:
>>
>>
>>
>> As you can see, the timestamp has the hundredths part filled in where as
>> the time part does not.
>>
>> I also tried binding to SQL_C_CHAR as a work-around. But this made no
>> difference, producing:
>>
>>
>>
>> This is the result of the same select statement run from pgAdmin III
>> showing that there the hundredths part is returned for both fields:
>>
>>
>
> Looks like this is the reason:
>
> https://msdn.microsoft.com/en-us/library/ms712436%28v=vs.85%29.aspx
>
> The identifier for the time ODBC SQL data type is:
>
> SQL_TYPE_TIME
>
> to
>
> SQL_C_TYPE_TIMESTAMP None[b] Data[c] 16[d]
>
> [c] The date fields of the timestamp structure are set to the
> current date, and the fractional seconds field of the timestamp
> structure is set to zero.
>
>
>>
>>
>> Cheers,
>> Scott
>>
>
>