Re: Obtaining hundredths of a second data from time data types

Interesting.  It looks like PostgreSQL is conforming to the
specification (unlike Microsoft SQL or SQL Anywhere).  However, it does
not help me with the underlying problem and that is "How do I get the
fractional part of a TIME field via ODBC?".

I have tried SQL_C_TYPE_TIMSTAMP, SQL_C_TYPE_CHAR and
SQL_C_TYPE_DEFAULT.  None of these return the fractional part of the
time field.  I've also tries SQL_C_TYPE_BINARY and get an error
szSqlState = "07006", *pfNativeError = 14, *pcbErrorMsg = 43,
MessageText = "Received an unsupported type from Postgres."

So how can I get the fractional information?

Note that I do not have any control of the SQL statement.  My code needs
to handle any statement and return all information about the query.

Cheers,
  Scott

On 05/03/2016 09:03, Adrian Klaver wrote:
> On 03/04/2016 01:20 PM, Scott Ferrett wrote:
>> Here is a screen shot from ODBCTest after Issuing "SELECT ts, t FROM
>> TestTable" and binding an SQL_C_TYPE_TIMESTAMP to each of the two
>> columns:
>>
>>
>>
>> As you can see, the timestamp has the hundredths part filled in where as
>> the time part does not.
>>
>> I also tried binding to SQL_C_CHAR as a work-around.  But this made no
>> difference, producing:
>>
>>
>>
>> This is the result of the same select statement run from pgAdmin III
>> showing that there the hundredths part is returned for both fields:
>>
>>
>
> Looks like this is the reason:
>
> https://msdn.microsoft.com/en-us/library/ms712436%28v=vs.85%29.aspx
>
> The identifier for the time ODBC SQL data type is:
>
> SQL_TYPE_TIME
>
> to
>
> SQL_C_TYPE_TIMESTAMP None[b] Data[c] 16[d]
>
> [c]   The date fields of the timestamp structure are set to the
> current date, and the fractional seconds field of the timestamp
> structure is set to zero.
>
>
>>
>>
>> Cheers,
>>   Scott
>>
>
>