Re: Using row_to_json with %ROWTYPE ?

On 02/05/2015 03:01 PM, Tim Smith wrote:
>   > returning more than one row? v_row can only hold one row at a time.
>
> Absolutley not.  (a) My where clause is a primary key (b) I have
> checked it manually, it only returns one row

Well since there was no error message provided and my psychic hat is in
the shop I had to start somewhere.

>
>> You really need to provide error messages
>
> Yes, well PostgreSQL is being incredibly unhelpful in that respect, it
> says "(SQLSTATE: 42702  - SQLERRM: column reference "session_id" is
> ambiguous)" ... but that is an utter lie.   There is only one column
> called session_id in my view (in both the view output and the
> underlying view query, there is only one reference to "session_id")

Actually I would say this is a pretty big clue that:

select row_to_json(v_row) from v_row;

is causing a problem. Try commenting it out and see what happens?

>
> On 5 February 2015 at 21:57, Adrian Klaver <adrian.klaver@aklaver.com> wrote:
>> On 02/05/2015 01:38 PM, Tim Smith wrote:
>>>
>>> Hi,
>>>
>>> I have a function that broadly looks like this :
>>>
>>> create function doStuff() returns json as $$
>>> DECLARE
>>> v_row my_view%ROWTYPE;
>>> BEGIN
>>> select * into strict v_row from my_view where foo=bar;
>>> select row_to_json(v_row) from v_row;
>>> END;
>>> $$ LANGUAGE plpgsql;
>>>
>>>
>>> However this does not seem to work ?   What am I doing wrong ?
>>
>>
>> Well for starters is:
>>
>> select * into strict v_row from my_view where foo=bar;
>>
>> returning more than one row? v_row can only hold one row at a time.
>>
>> Given that then:
>>
>> select row_to_json(v_row) from v_row;
>>
>> should be:
>>
>> select row_to_json(v_row);
>>
>> I would suggest taking a look at:
>>
>> http://www.postgresql.org/docs/9.3/interactive/plpgsql-control-structures.html#PLPGSQL-RECORDS-ITERATING
>>
>>
>> Also error messages would be helpful:)
>>
>>
>>>
>>> Thanks
>>>
>>> Tim
>>>
>>>
>>
>>
>> --
>> Adrian Klaver
>> adrian.klaver@aklaver.com


--
Adrian Klaver
adrian.klaver@aklaver.com