Re: Add min and max execute statement time in pg_stat_statement
От | Andrew Dunstan |
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Тема | Re: Add min and max execute statement time in pg_stat_statement |
Дата | |
Msg-id | 54BED71D.4050302@dunslane.net обсуждение исходный текст |
Ответ на | Re: Add min and max execute statement time in pg_stat_statement (Arne Scheffer <arne.scheffer@uni-muenster.de>) |
Ответы |
Re: Add min and max execute statement time in pg_stat_statement
Re: Add min and max execute statement time in pg_stat_statement |
Список | pgsql-hackers |
On 01/20/2015 01:26 PM, Arne Scheffer wrote: > Interesting patch. > I did a quick review looking only into the patch file. > > The "sum of variances" variable contains > the "sum of squared differences" instead, I think. Umm, no. It's not. e->counters.sum_var_time += (total_time - old_mean) * (total_time - e->counters.mean_time); This is not a square that's being added. old_mean is not the same as e->counters.mean_time. Since the variance is this value divided by (n - 1), AIUI, I think "sum of variances" isn't a bad description. I'm open to alternative suggestions. > > And a very minor aspect: > The term "standard deviation" in your code stands for > (corrected) sample standard deviation, I think, > because you devide by n-1 instead of n to keep the > estimator unbiased. > How about mentioning the prefix "sample" > to indicate this beiing the estimator? I don't understand. I'm following pretty exactly the calculations stated at <http://www.johndcook.com/blog/standard_deviation/> I'm not a statistician. Perhaps others who are more literate in statistics can comment on this paragraph. > > And I'm sure I'm missing C specifics (again) > (or it's the reduced patch file scope), > but you introduce sqrtd, but sqrt is called? Good catch. Will fix. cheers andrew
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