Re: row literal problem
От | Andrew Dunstan |
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Тема | Re: row literal problem |
Дата | |
Msg-id | 50071FC8.1060806@dunslane.net обсуждение исходный текст |
Ответ на | Re: row literal problem (Tom Lane <tgl@sss.pgh.pa.us>) |
Ответы |
Re: row literal problem
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Список | pgsql-hackers |
On 07/18/2012 03:30 PM, Tom Lane wrote: > Andrew Dunstan <andrew@dunslane.net> writes: >> On 07/18/2012 03:18 PM, Merlin Moncure wrote: >>> there are no null fields, right? if the last field is sometimes null >>> you'd see that (you probably ruled that out though). when you say >>> 'sometimes', do you mean for some rows and not others? or for some >>> queries? >> No, the inner query has two fields. >> It happens for all rows, but not for all two-field-resulting queries as >> q. I'm trying to find a simple case rather than the rather complex query >> my customer is using. > I'm wondering about a rowtype with a third, dropped column. As usual Tom has hit the nail on the head. Here's a simple test case that demonstrates the problem. I could probably have cut it down more but I was following the structure of the original somewhat: # with q as ( select max(nspname) as nspname, sum(allind.count) as indices from (select indrelid, count(*) from pg_index group by indrelid) allind left outer join pg_class on pg_class.oid = allind.indrelid left outer join pg_namespace on pg_class.relnamespace = pg_namespace.oid group by pg_namespace.oid ) select q from q; q -------------------- (pg_catalog,91,11) (pg_toast,18,99) (2 rows) cheers andrew > > regards, tom lane >
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