Re: How to do?
От | Robert Partyka |
---|---|
Тема | Re: How to do? |
Дата | |
Msg-id | 5.1.0.14.0.20030801182222.00a0bec0@mail.alpha.pl обсуждение исходный текст |
Ответ на | How to do? (Robert Partyka <R.Partyka@wdg.pl>) |
Ответы |
Re: How to do?
Re: How to do? |
Список | pgsql-general |
Ron Johnson wrote: > No, but slightly ambiguous, at least for my old brain. I will try to by more unequivocal this time :) Shridhar Daithankar wrote: > select oid,name from a; I know it, but i have to have not oid's but row numbers :) such like : table "test" offset | value -----------+------------ 1 | AC43 2 | AC4X 3 | AX43 4 | ACX3 .... n | XC4A the best will be without using sequence :) Shridhar Daithankar wrote: > I didn't get that.. could you please elaborate? Franco Bruno Borghesi wrote: > And about the rows before and after that you ask, I don't understand... based on what you mean > *before* and *after*? you don't have an order by clause. > And what do you mean with "I know that in result is record with e.g. uid='AC13A1'"? > You know this uid *before* sending the query? is it part of your <where statement>? can you use > this value as a hard coded condition for a subquery? Ok, so its goes something like that: lets say i have select query: select a,b,uid from foo where c='bar' order by a; with results like that: a | b | uid ----+----+------ 2 |x | AC01 2 |w | AC43 4 |d | AC88 4 |a | AC13 ... 7 |c | AC22 and lets say I selected this before and I know that there is uid='AC88'; and in another connection (in lets say next requested www php script ) without selecting all this data or even full list of only uid`s and making sequence scan row by row I wont to get something like that from select I have write above: a | b | uid ----+----+------ 2 |w | AC43 4 |d | AC88 4 |a | AC13 (3 rows) if there is row before and row next of uid='AC88' or a | b | uid ----+----+------ 2 |w | AC43 4 |d | AC88 (2 rows) if uid='AC88' is last one row or a | b | uid ----+----+------ 4 |d | AC88 4 |a | AC13 (2 rows) if uid='AC88' is first row I hope its more understandable than before :) regards Robert 'BoBsoN' Partyka
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