Re: Why HDD performance is better than SSD in this case
От | Mark Kirkwood |
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Тема | Re: Why HDD performance is better than SSD in this case |
Дата | |
Msg-id | 4fc347b1-a7f9-c0cf-58e6-99f0c37028b2@catalyst.net.nz обсуждение исходный текст |
Ответ на | Why HDD performance is better than SSD in this case (Neto pr <netopr9@gmail.com>) |
Список | pgsql-performance |
Can you post make and model of the SSD concerned? In general the cheaper consumer grade ones cannot do sustained read/writes at anything like their quoted max values. regards Mark On 17/07/18 17:00, Neto pr wrote: > Dear, > Some of you can help me understand this. > > This query plan is executed in the query below (query 9 of TPC-H > Benchmark, with scale 40, database with approximately 40 gb). > > The experiment consisted of running the query on a HDD (Raid zero). > Then the same query is executed on an SSD (Raid Zero). > > Why did the HDD (7200 rpm) perform better? > HDD - TIME 9 MINUTES > SSD - TIME 15 MINUTES > > As far as I know, the SSD has a reading that is 300 times faster than SSD. > > --- Execution Plans--- > ssd 40g > https://explain.depesz.com/s/rHkh > > hdd 40g > https://explain.depesz.com/s/l4sq > > Query ------------------------------------ > > select > nation, > o_year, > sum(amount) as sum_profit > from > ( > select > n_name as nation, > extract(year from o_orderdate) as o_year, > l_extendedprice * (1 - l_discount) - ps_supplycost * > l_quantity as amount > from > part, > supplier, > lineitem, > partsupp, > orders, > nation > where > s_suppkey = l_suppkey > and ps_suppkey = l_suppkey > and ps_partkey = l_partkey > and p_partkey = l_partkey > and o_orderkey = l_orderkey > and s_nationkey = n_nationkey > and p_name like '%orchid%' > ) as profit > group by > nation, > o_year > order by > nation, > o_year desc >
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