Re: Get the max viewd product_id for user_id

On 12/03/2010 12:40 PM, Jayadevan M wrote:
> Hello,
>
>> I went this way, but for a large number of user_id's, it's quite slow:
>>
>> CREATE VIEW v_views AS
>>     SELECT user_id, product_id, count(*) as views
>>     FROM viewlog
>>     GROUP BY user_id, product_id
>>
>> SELECT
>>     DISTINCT user_id,
>>     (SELECT product_id FROM v_views inn WHERE inn.user_id = out.user_id
>> ORDER BY views DESC LIMIT 1) as product_id,
>>     (SELECT views FROM v_views inn WHERE inn.user_id = out.user_id ORDER
> BY
>> views DESC LIMIT 1) as views
>> FROM
>>     v_views out
>>
> Does this work faster?
> select x.user_id,y.product_id,x.count from
> (select user_id, max(count ) as count from (select user_id,product_id,
> count(*) as count from viewlog group by user_id,product_id) as x group by
> user_id
> ) as x inner join
> (select user_id,product_id, count(*) as count1 from viewlog group by
> user_id,product_id ) as y
> on x.user_id=y.user_id and x.count=y.count1
>

It does, yes. Actually, pretty silly of me not to implement it that way, 
thank you.

Since I already have the view, the query now looks like this:


selectx.user_id,y.product_id,x.views
from (select    user_id,    max(views) as viewsfrom    v_viewsgroup by    user_id
) as xinner join v_views as yon x.user_id=y.user_id and x.views=y.views

And CTEs would also help here :)
Mario