Re: SUM the result of a subquery.

<font face="Verdana">Wow, I had no idea about this kind of SELECT expression. It works flawless!!! Thank you lots
Jayadevan</font><fontface="Verdana"> :) .</font><br /><font face="Verdana"><br /></font><br /> On 02/09/10 14:28,
JayadevanM wrote: <blockquote cite="mid:OF39AE7609.CC04F696-ON65257792.00446E7D-65257792.00448A26@ibsplc.com"
type="cite"><blockquotetype="cite"><pre wrap="">SELECT SUM (
 
(SELECT i.id_item, i.price, SUM (o.quantity), ROUND (SUM 
(o.quantity) * i.price, 2) AS cost
FROM orders o
JOIN items i ON i.id_item = o.id_item
WHERE o.date_order BETWEEN '2010-01-01' AND '2010-01-31'
GROUP BY i.id_item, i.price)
); 

No luck. Obviously SUM expects an expression, not a set of rows. Is 
there a way to perform a sum of the resulting rows?
   </pre></blockquote><pre wrap="">I don't have a PostgreSQL server to try this right now. But you are 
looking for something like 
SELECT SUM (cost) from (
(SELECT i.id_item, i.price, SUM (o.quantity), ROUND (SUM (o.quantity) * 
i.price, 2) AS cost
FROM orders o
JOIN items i ON i.id_item = o.id_item
WHERE o.date_order BETWEEN '2010-01-01' AND '2010-01-31'
GROUP BY i.id_item, i.price)
) as x

Regards,
Jayadevan





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