Re: optimizing daily data storage in Pg
От | Andy Colson |
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Тема | Re: optimizing daily data storage in Pg |
Дата | |
Msg-id | 4C48BE88.80203@squeakycode.net обсуждение исходный текст |
Ответ на | optimizing daily data storage in Pg (P Kishor <punk.kish@gmail.com>) |
Ответы |
Re: optimizing daily data storage in Pg
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Список | pgsql-general |
On 7/22/2010 9:41 AM, P Kishor wrote: > I have been struggling with this for a while now, have even gone down > a few paths but struck out, so I turn now to the community for ideas. > First, the problem: Store six daily variables for ~ 25 years for cells > in a grid. > > * Number of vars = 6 > * Number of cells ~ 13 million > * Number of days ~ 9125 (25 * 365) > > Optimize the store for two different kinds of queries: > > Query one: Retrieve the value of a single var for all or a portion of > the cells for a single day. This is analogous to an image where every > pixel is the value of a single var. > SELECT<var> FROM d WHERE yr = ? AND yday = ?; > SELECT<var> FROM d WHERE yr = ? AND yday = ? AND cell_id IN (?,?,?...); > > Query two: Retrieve values for all the days or a duration of days for > a single var for a single cell. This is like grabbing a column out of > a table in which each row holds all the vars for a single day. > SELECT<var> FROM d WHERE cell_id = ?; > SELECT<var> FROM d WHERE cell_id IN (?,?,?...); First, I must admit to not reading your entire email. Second, Query 1 should be fast, regardless of how you layout the tables. Third, Query 2 will return 13M rows? I dont think it matters how you layout the tables, returning 13M rows is always going to be slow. -Andy
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