Many-to-many problem
От | Raymond O'Donnell |
---|---|
Тема | Many-to-many problem |
Дата | |
Msg-id | 4BA2AE2B.2070602@iol.ie обсуждение исходный текст |
Ответы |
Re: Many-to-many problem
Re: Many-to-many problem |
Список | pgsql-general |
G'night all, I'm being driven nuts by an SQL problem which I think ought to be simple, but I can't see the answer. I have two tables related many-to-many via a third - they describe a set of users, a set of applications and which users have been granted access to which applications. What I want is to create a view which lists all users and the applications to which they *don't* have access. CREATE TABLE apps ( appcode character varying(16) NOT NULL, appnameshort character varying(32) NOT NULL, ... CONSTRAINT apps_pk PRIMARY KEY (appcode) ); CREATE TABLE users ( uid character varying(16) NOT NULL, surname character varying(32) NOT NULL, firstname character varying(32) NOT NULL, ... CONSTRAINT users_pkey PRIMARY KEY (uid) ); CREATE TABLE canaccess ( uid character varying(16) NOT NULL, appcode character varying(16) NOT NULL, pwd character varying(16) NOT NULL, CONSTRAINT canaccess_pk PRIMARY KEY (uid, appcode), CONSTRAINT appcode_fk FOREIGN KEY (appcode) REFERENCES apps (appcode) MATCH SIMPLE ON UPDATE NO ACTION ON DELETE NO ACTION, CONSTRAINT uid_fk FOREIGN KEY (uid) REFERENCES users (uid) MATCH SIMPLE ON UPDATE NO ACTION ON DELETE NO ACTION ); I can do it easily enough for one user; my problem is doing it for all users in one fell swoop. I'm sure this is a very common problem, but I just can't see the solution, so any pointers would be greatly appreciated. Many thanks in advance.... Ray. -- Raymond O'Donnell :: Galway :: Ireland rod@iol.ie
В списке pgsql-general по дате отправления: