Re: help with SQL join
От | John R Pierce |
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Тема | Re: help with SQL join |
Дата | |
Msg-id | 4B74620B.9090807@hogranch.com обсуждение исходный текст |
Ответ на | help with SQL join (Neil Stlyz <neilstylz@yahoo.com>) |
Ответы |
Re: help with SQL join
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Список | pgsql-general |
Neil Stlyz wrote: > Now... here is the problem I am having... the above SQL query is > retrieving results from one table: sales > I have another table called customers with a couple of fields > (customerid, and customername are two of the fields). > I want to join on the customerid in both tables to retrieve the > customername in the query. > So I need the results to look something like this: > > customerid | customername | > TODAYS_USERS | LAST 7 DAYS | LAST 30 DAYS > bigint | varchar | > bigint | bigint > | bigint > -------------------------------------------------------------------------------------------------------------------------------- > 8699 | Joe Smith | 1 > | > 1 | 1 > 8700 | Sara Olson | 1 > | 12 > | 17 > 8701 | Mike Jones | 3 > | > 5 | 19 > > Can someone show me how to use a JOIN with the above SQL Statement? I > need to bring the customername field into the query from the other > table and I have been having issues writting the query... can this > even be done? something like... SELECT results.customerid, c.customername, count(distinct count1) AS "TODAYS_USERS", count(distinct count2) AS "LAST 7 DAYS" , count(distinct count3) AS "LAST 30 DAYS" FROM (SELECT distinct case when s.modified >= '2010-02-11' then s.modelnumber else null end as count1, case when s.modified >= '2010-02-04' then s.modelnumber else null end as count2, case when s.modified >= '2010-01-11' then s.modelnumber else null end as count3, s.customerid FROM sales as s WHERE s.modelnumber LIKE 'GH77%') AS results JOIN customers as c ON (results.customerid = c.customerid) GROUP BY results.customerid
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