Re: FUNCTION problem

Adrian Klaver wrote:
> On Friday 03 April 2009 6:51:05 am Adrian Klaver wrote:
>> On Thursday 02 April 2009 6:16:44 pm Adrian Klaver wrote:
>>> Now I remember. Its something that trips me up, the RECORD in RETURN
>>> setof RECORD is not the same thing as the RECORD in DECLARE RECORD. See
>>> below for a better explanation-
>>> http://www.postgresql.org/docs/8.3/interactive/plpgsql-declarations.html#
>>> PL PGSQL-DECLARATION-RECORDS Note that RECORD is not a true data type,
>>> only a placeholder. One should also realize that when a PL/pgSQL function
>>> is declared to return type record, this is not quite the same concept as
>>> a record variable, even though such a function might use a record
>>> variable to hold its result. In both cases the actual row structure is
>>> unknown when the function is written, but for a function returning record
>>> the actual structure is determined when the calling query is parsed,
>>> whereas a record variable can change its row structure on-the-fly.
>>>
>>>
>>>
>>> --
>>> Adrian Klaver
>>> aklaver@comcast.net
>> For this particular case the following works.
>>
>> CREATE OR REPLACE FUNCTION test_function(integer) RETURNS record
>>     AS $Body$
>> DECLARE croid integer;
>> DECLARE R RECORD;
>> BEGIN
>>     SELECT INTO croid 2;
>>     SELECT INTO R  croid,$1;
>> RETURN R;
>> END;
>>
>> $Body$
>>     LANGUAGE plpgsql;
>>
>> --
>> Adrian Klaver
>> aklaver@comcast.net
> 
> Forgot to show how to call it.
> 
> test=# SELECT * from test_function(1) as test(c1 int,c2 int);
>  c1 | c2
> ----+----
>   2 |  1
> (1 row)
> 
> 

Ah!, I see what you mean about the definition of 'RECORD'.
(The lights come on...)

And here I thought it would all be so simple.....

You show a valid, and most informative solution.
This should get things working for me.

Thank you very much for your help.

Peter